(PHP 8 >= 8.3.0)
json_validate — Checks if a string contains valid JSON
$json, int $depth = 512, int $flags = 0): bool
Returns whether the given string is syntactically valid JSON.
If json_validate() returns true, json_decode()
will successfully decode the given string when using the same
depth and flags.
If json_validate() returns false, the cause
can be retrieved using json_last_error() and
json_last_error_msg().
json_validate() uses less memory than json_decode() if the decoded JSON payload is not used, because it does not need to build the array or object structure containing the payload.
Calling json_validate() immediately before json_decode() will unnecessarily parse the string twice, as json_decode() implicitly performs validation during decoding.
json_validate() should therefore only be used if the decode JSON payload is not immediately used and knowing whether the string contains valid JSON is needed.
jsonThe string to validate.
This function only works with UTF-8 encoded strings.
Замечание:
PHP реализует надмножество JSON, который описан в первоначальном » RFC 7159.
depth
Maximum nesting depth of the structure being decoded.
The value must be greater than 0,
and less than or equal to 2147483647.
flags
Currently only
JSON_INVALID_UTF8_IGNORE
is accepted.
Returns true if the given string is syntactically valid JSON, otherwise
returns false.
If depth is outside the allowed range,
a ValueError is thrown.
Пример #1 json_validate() examples
<?php
var_dump(json_validate('{ "test": { "foo": "bar" } }'));
var_dump(json_validate('{ "": "": "" } }'));
?>Результат выполнения данного примера:
bool(true) bool(false)